Showing Page:
1/5
Running head: SUBJECTIVE TEST QUESTIONS 1
Subjective Test Questions
Student Name
Institutional Affiliation
Showing Page:
2/5
SUBJECTIVE TEST QUESTIONS 2
Q1
No, it is not reasonable to calculate a confidence interval for the data.
Reason: the population standard deviation is not given.
Q2
We are given:
Margin of estimate, e = 0.10(100) hours
Level of confidence, C.I = 95%
Standard deviation, = 0.90 hours
Sample size, n =?
Sample size = 󰇡

󰇢
But at 95% level of confidence, z = 1.96 from tables
Hence,
n = 󰇡


󰇢
= 311.1696
Therefore, the required sample size is 312.
Q3
We are given:
X=120
N=200
Sample proportion, p=
=


=0.6
Confidence interval of a population proportion = z
󰇛󰇜
95% confidence interval = 0.61.96*
󰇛󰇜

Showing Page:
3/5
SUBJECTIVE TEST QUESTIONS 3
95% confidence interval =0.60.0679
95% confidence interval = (0.5321, 0.6679)
Yes. The proportion of the Georgetown country residents who believe that country’s real estate
taxes are too high is between 0.5321 and 0.6679 at 95% level of confidence.
Q4
First, state the null and alternative hypothesis
:
(No significant difference in the mean selection sales)
:
(Atleast one of the means of the selection sales is different)
Where;
= the mean for soft drink selection sales
= the mean for new registers sales
=the mean for dairy selection sales
To test where a significant difference exists, a one-way ANOVA model is conducted using Ms-
Excel.
Anova: Single
Factor
SUMMARY
Groups
Count
Sum
Average
Variance
Column 1
5
40
8
11.5
Column 2
5
35
7
6.5
Column 3
5
43
8.6
4.3
ANOVA
Source of
Variation
SS
df
MS
F
P-value
F crit
Between
Groups
6.5333333
2
3.2666667
0.439462
0.65435
3.885294
Within Groups
89.2
12
7.4333333
Showing Page:
4/5
SUBJECTIVE TEST QUESTIONS 4
Total
95.733333
14
Decision rule at 5% significance level: Reject the null hypothesis if F> F critical (Kreyszig,
2010).
F=0.439
F critical = 3.885
Since F observed is less than F critical, we fail to reject the null hypothesis since we do not have
enough evidence. Therefore we conclude that there is no significant difference in the mean
selection of Coca-Cola stacked at four locations of the store.
Showing Page:
5/5
SUBJECTIVE TEST QUESTIONS 5
Reference
Kreyszig, E. (2010). Advanced Engineering Mathematics, 10th Edition. John Wiley & Sons.

Unformatted Attachment Preview

Running head: SUBJECTIVE TEST QUESTIONS Subjective Test Questions Student Name Institutional Affiliation 1 SUBJECTIVE TEST QUESTIONS 2 Q1 No, it is not reasonable to calculate a confidence interval for the data. Reason: the population standard deviation is not given. Q2 We are given: Margin of estimate, e = 0.10(100) hours Level of confidence, C.I = 95% Standard deviation, 𝜎 = 0.90 hours Sample size, n =? 𝑧∗𝜎 2 Sample size = ( 𝑒 ) But at 95% level of confidence, z = 1.96 from tables Hence, 1.96∗0.90 2 n=( 0.10 ) = 311.1696 Therefore, the required sample size is 312. Q3 We are given: X=120 N=200 𝑋 120 Sample proportion, p=𝑁 = 200=0.6 𝑝(1−𝑝) Confidence interval of a population proportion = 𝑝 ±z√ 0.6(1−0.6) 95% confidence interval = 0.6±1.96*√ 200 𝑛 SUBJECTIVE TEST QUESTIONS 3 95% confidence interval =0.6±0.0679 95% confidence interval = (0.5321, 0.6679) Yes. The proportion of the Georgetown country residents who believe that country’s real estate taxes are too high is between 0.5321 and 0.6679 at 95% level of confidence. Q4 First, state the null and alternative hypothesis H0 : 𝜇0 = 𝜇1 = 𝜇2 (No significant difference in the mean selection sales) H1 : 𝜇0 ≠ 𝜇1 ≠ 𝜇2 (Atleast one of the means of the selection sales is different) Where; 𝜇0 = the mean for soft drink selection sales 𝜇1 = the mean for new registers sales 𝜇2 =the mean for dairy selection sales To test where a significant difference exists, a one-way ANOVA model is conducted using MsExcel. Anova: Single Factor SUMMARY Groups Column 1 Column 2 Column 3 ANOVA Source of Variation Between Groups Within Groups Count 5 5 5 SS 6.5333333 89.2 Sum 40 35 43 df Average Variance 8 11.5 7 6.5 8.6 4.3 MS 2 12 F P-value F crit 3.2666667 0.439462 0.65435 3.885294 7.4333333 SUBJECTIVE TEST QUESTIONS Total 95.733333 4 14 Decision rule at 5% significance level: Reject the null hypothesis if F> F critical (Kreyszig, 2010). F=0.439 F critical = 3.885 Since F observed is less than F critical, we fail to reject the null hypothesis since we do not have enough evidence. Therefore we conclude that there is no significant difference in the mean selection of Coca-Cola stacked at four locations of the store. SUBJECTIVE TEST QUESTIONS 5 Reference Kreyszig, E. (2010). Advanced Engineering Mathematics, 10th Edition. John Wiley & Sons. Name: Description: ...
User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service.
Studypool
4.7
Trustpilot
4.5
Sitejabber
4.4