Find a model for simple harmonic motion that has an initial displacement (t=0) of 0 inches, an amplitude of 6 inches, and a frequency 2/3 cycles per second.: * Answers are: d=6cos((4pi/3)*t) d=6sin((4pi/3)*t) d=6cos((3pi/4)*t) d=6sin((3pi/4)*t) Solution harmonic motion can take the form of either: y = Asin(B(t - C)) + D or y = Acos(B(t - C)) + D |A| = amplitude 2pi/|B| = period C = horizontal shift or phase shift D = vertical shift |A| = 6 since amplitude is given Initial displacement of 0 at t = 0 means D = 0 (no vertical shift). It also means you want a sine curve because regular cosi ...
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