Access Millions of academic & study documents

1 ) solve for x, y, z please show how to do without calculator 7x+

Content type
User Generated
Showing Page:
1/4
1.) solve for x, y, z please show how to do without
calculator
7x+3y+7=39
5x+3y+2z=36
2x+3z=23
2.) you have a bag of 77 nickles and dimes worth 5$. how
many coins of each type do you have? please show how to
make an equation and work
3.) solve for x,y,z please show how to do with out
calculator
2x+3y+z=11
x+2y-z=11
3x+y+2z=8
Solution
Cramster allows 1 question per post:
I will demonstrate the methods for solving 1 and 3,
and then show all the steps for 2.
1) For questions 1 and 3, these are system of equation
problems.
These can be solved by substitution or elimination.
In this casem elimination looks like a good method:
7x+3y+7=39

Sign up to view the full document!

lock_open Sign Up
Showing Page:
2/4
5x+3y+2z=36
2x+3z=23
2) Start with these two:
Combine like terms to get into the right form:
7x+3y+7=39 =>becomes => 7x+3y=32
5x+3y+2z=36
3) Subtract one from the other, the whole thing:
7x+3y =32
- (5x+3y+2z=36)
2x+0y -2z=-4
2x-2z=-4
4) Now, do the same process with this answer
and the third equation from the beginning of the question:
2x-2z =-4
- (2x+3z =23)
0x-5z=-27
-5z=-27
z=(27/5)
5) Substitute this into one of the original equations:
5x+3y+2z=36 => becomes => 5x+3y+2(27/5) = 36
Use these same steps (1 thru 5) to solve the system of

Sign up to view the full document!

lock_open Sign Up
Showing Page:
3/4

Sign up to view the full document!

lock_open Sign Up
End of Preview - Want to read all 4 pages?
Access Now
Unformatted Attachment Preview
1.) solve for x, y, z please show how to do without calculator 7x+3y+7=39 5x+3y+2z=36 2x+3z=23 2.) you have a bag of 77 nickles and dimes worth 5$. how many coins of each type do you have? please show how to make an equation and work 3.) solve for x,y,z please show how to do with out calculator 2x+3y+z=11 x+2y-z=11 3x+y+2z=8 Solution Cramster allows 1 question per post: I will demonstrate the methods for solving 1 and 3, and then show all the steps for 2. 1) For questions 1 and 3, these are system of equation problems. These can be solved by substitution or elimination. In this casem elimination looks like a good method: 7x+3y+7=39 5x+3y+2z=36 2x+3z=23 2) Start with these two: Combine like terms to get into the right form: 7x+3y+7=39 =>becomes => 7x+3y=32 5x+3y+2z=36 3) Subtract one from the other, the whole thing: 7x+3y =32 - (5x+3y+2z=36) 2x+0y -2z=-4 2x-2z=-4 4) Now, do the same process with this answer and the third equation from the beginning of the question: 2x-2z =-4 - (2x+3z =23) 0x-5z=-27 -5z=-27 z=(27/5) 5) Substitute this into one of the original equations: 5x+3y+2z=36 => becomes => 5x+3y+2(27/5) = 36 Use these same steps (1 thru 5) to solve the system of eq ...
Purchase document to see full attachment
User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service.
Studypool
4.7
Indeed
4.5
Sitejabber
4.4