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MTH 209 week 4 individual assignment

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9.1 #84
3
1000
36^27 y
=
3
3
1000
36^27 y
=
3
3
3^10
36^*3^3 y
=
10
3y^12-
9.2 #104
(-27x^9)^1/3
Using the power of exponent rule, we divide the internal exponent by 3
-27x^3
Answer:
33/93/13/19
3)27()27( xxx
==
9.3 # 94
(3-
2
7
)(3+
2
7
) =
9 +
6
7
-
6
7
-
4
49
=
9 – 4(7) = 9 -28 =
-19
9.4 #76
7
6
*
3
14
=
7
6
* (
3
14
*
)=
7
6
*
6
28
=
7
28
*
7
7
=
7
28

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Answer:
2
3
72
7
32
3
14
7
6
==
9.5 #32
3
1
+
w
=6 =
3^2
1
+
w
^2=6^2 =
9(w+1) = 36 =
9w+9=36 =
9w+9-9=36-9
9w=27
9w/9=27/9
w=3
10.1 #96
297
+
x
=x+3
297
+
x
^2=(x+3)^2
7x+29 = x^2+9
0=x^2-7x-20
20=x^2-7x
(7/2)^2 = 14/4
20+14/4 = 14/4 + x^2 – 7x
80/4 + 14/4 = (x-7/2)^2
94/4 = (x-7/2)^2
+-
4
94
= x-7/2
x= 7/2 +/-
2
94
x=
2
947
+
,
2
947
Answer:

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9.1 #84 = = = 9.2 #104 (-27x^9)^1/3 Using the power of exponent rule, we divide the internal exponent by 3 -27x^3 Answer: 9.3 # 94 (3-)(3+) = 9 +--= 9 - 4(7) = 9 -28 = -19 9.4 #76 *= * (*)= *= *= Answer: 9.5 #32 3=6 = 3^2^2=6^2 = 9(w+1) = 36 = 9w+9=36 = 9w+9-9=36-9 9w=27 9w/9=27/9 w=3 10.1 #96 =x+3 ^2=(x+3)^2 7x+29 = x^2+9 0=x^2-7x-20 20=x^2-7x (7/2)^2 = 14/4 20+14/4 = 14/4 + x^2 - 7x 80/4 + 14/4 = (x-7/2)^2 94/4 = (x-7/2)^2 +-= x-7/2 x= 7/2 +/- x= , Answer: or -4 does not check, so the solution set is {5} 10.2 #48 -3x^2+7x=0 -3x^2+7x+0=0 7^2-4(-3)(0) 49-0=0 49 with 2 real solutions 10.3 #70 b^4+13b^2+36=0 w^2+13w+36=0 (w+4)(w+9)=0 w+4=0 w+9=0 w=-4 w=-9 b^2=-4 b^2= -9 Solution set is 2,-2,3,-3 Answer: or Solution set Score Sheet Section 9.1 Exercises: 84 12.50 12.50 Section 9.2 Exercises: 104 12.50 4.00 Section 9.3 Exercises: 94 12.50 12.50 Section 9.4 Exercises: 76 12.50 4.00 Section 9.5 Exercises: 32 12.50 12.50 Section 10.1 Exercise: 96 12.50 4.00 Section 10.2 Exercise: 48 12.50 12.50 Section 10.3 Exercise: 70 12.50 8.50 ? 100.00 70.50 3.00 2.12 ...
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