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# MTH 209 week 4 individual assignment

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9.1 #84
3
1000
36^27 y
=
3
3
1000
36^27 y
=
3
3
3^10
36^*3^3 y
=
10
3y^12-
9.2 #104
(-27x^9)^1/3
Using the power of exponent rule, we divide the internal exponent by 3
-27x^3
33/93/13/19
3)27()27( xxx
==
9.3 # 94
(3-
2
7
)(3+
2
7
) =
9 +
6
7
-
6
7
-
4
49
=
9 – 4(7) = 9 -28 =
-19
9.4 #76
7
6
*
3
14
=
7
6
* (
3
14
*
)=
7
6
*
6
28
=
7
28
*
7
7
=
7
28

2
3
72
7
32
3
14
7
6
==
9.5 #32
3
1
+
w
=6 =
3^2
1
+
w
^2=6^2 =
9(w+1) = 36 =
9w+9=36 =
9w+9-9=36-9
9w=27
9w/9=27/9
w=3
10.1 #96
297
+
x
=x+3
297
+
x
^2=(x+3)^2
7x+29 = x^2+9
0=x^2-7x-20
20=x^2-7x
(7/2)^2 = 14/4
20+14/4 = 14/4 + x^2 – 7x
80/4 + 14/4 = (x-7/2)^2
94/4 = (x-7/2)^2
+-
4
94
= x-7/2
x= 7/2 +/-
2
94
x=
2
947
+
,
2
947

0)4)(5(
200
96297
)3()297(
3297
2
2
22
=+
=
++=+
+=+
+=+
xx
xx
xxx
xx
xx
5
05
=
=
x
x
or
4
04
=
=+
x
x
-4 does not check, so the solution set is {5}
10.2 #48
-3x^2+7x=0
-3x^2+7x+0=0
7^2-4(-3)(0)
49-0=0
49 with 2 real solutions
10.3 #70
b^4+13b^2+36=0
w^2+13w+36=0
(w+4)(w+9)=0
w+4=0 w+9=0
w=-4 w=-9
b^2=-4 b^2= -9
Solution set is 2,-2,3,-3
0)4)(9(
03613
22
24
=++
=++
bb
bb
ib
b
b
3
9
09
2
2
±=
=
=+
or
ib
b
b
2
4
04
2
2
±=
=
=+
Solution set
}{
ii 3,2
±±

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Anonymous
Really useful study material!

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