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2x^ 5x= 2Solutionx=1by dividing both sides by 2 you get

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2x^-5x=-2
Solution
x=1
by dividing both sides by -2 you get:
-x^-5x = 1, which can be rewritten as -1/(x^5x)=1
As you can see, you now need a denominator equal to -1,
because -1/-1=1
so x^5x=1
you can quickly look at this and conclude that x has to be -
1 or 1. (if x > 1 or x<-1 then obviously the abosolute value
would increase even further. If -1<x<1 then x would
obviously be less than one)
As with most questions of the sort that x^(any number)=0
or 1 you will pretty much alwasy have 0 or 1 or -1 as your
answer.

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2x^-5x=-2 Solution x=1 by dividing both sides by -2 you get: -x^-5x = 1, which can be rewritten as -1/(x^5x)=1 As you can see, you now need a denominator equal to -1, because -1/-1=1 so x^5x=1 you can quickly look at this and conclude that x has to be 1 or 1. (if x > 1 or x ...
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Anonymous
Awesome! Perfect study aid.

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