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How do you do Ln(t) ln(t 7)=1Solutionln(a) ln(b)=ln(ab)t

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How do you do :
Ln(t)-ln(t-7)=1
Solution
ln(a)-ln(b)=ln(a/b)
therefore, ln(t)-ln(t-7)=ln(t/t-7)
now, ln(t/t-7)=1
implies, t/(t-7)=e^1
implies, t=te-7e
,t=7e/(e-1)

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How do you do : Ln(t)-ln(t-7)=1 Solution ln(a)-ln(b)=ln(a/b) therefore, ln(t)-ln(t-7)=ln(t/t-7) now, ln(t/t-7)=1 implies, t/(t-7)=e^1 implies, t=te-7e ,t=7e/(e-1) Name: Description: ...
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