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5 (C++ Program Please) Develop a function called reCount, with the

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5. (C++ Program Please) Develop a function called
reCount, with the prototype: bool reCount(const char *S,
char *P);
Functionally, it accepts two c-strings, and it searches
string S for the occurrence of the pattern string, P: if found
at least once it will return true.
Example:
char *acid = \"UTTAGUATGUUU\";
bool found;
found = reCount(acid, \"TAG); // found will be true
found = reCount(acid, \"TGA\"); // found will be false
found = reCount(acid, \"GUUU\"); // found will be true
Solution
bool reCount(const char *S, char *P)
{int i,j,temp;
for(i=0;S[i]!=\'\';i++)
{
j=0;
if(S[i]==P[j])
{
temp=i+1;
while(S[i]==P[j])
{

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i++;
j++;
}
if(P[j]==\'\')
{
cout<<\"The substring is present in given string
\"<<temp<<\"n\";
return true;
exit(0);
}
else
{
i=temp;
temp=0;
}
}
}
if(temp==0)
{ cout<<\"The substring is not present in given strinn\";
return false;
}
}

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5. (C++ Program Please) Develop a function called reCount, with the prototype: bool reCount(const char *S, char *P); Functionally, it accepts two c-strings, and it searches string S for the occurrence of the pattern string, P: if found at least once it will return true. Example: char *acid = \"UTTAGUATGUUU\"; bool found; found = reCount(acid, \"TAG); // found will be true found = reCount(acid, \"TGA\"); // found will be false found = reCount(acid, \"GUUU\"); // found will be true Solution bool reCount(const char *S, char *P) {int i,j,temp; for(i=0;S[i]!=\'\';i++) { j=0; if(S[i]==P[j]) { temp=i+1; while(S[i]==P[j]) { i++; j++; } if(P[j]==\'\') { cout ...
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