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6 Suppose a disk drive has the following characteristics • 6 surfa

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6. Suppose a disk drive has the following characteristics:
6 surfaces 1024 tracks per surface 128 sectors per
track 512 bytes/sector Track-to-track seek time of 10
milliseconds Rotational speed of 6000 RPM. a. What is
the capacity of the drive? b. What is the access time? .
Solution
a) The capacity of the drive=
6*1024*128*512=384MB
b)Rotational delay =
((60/6000RPM)*(1000/second))/2 =5ms
Access time=5ms+10ms= 15ms

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6. Suppose a disk drive has the following characteristics: • 6 surfaces • 1024 tracks per surface • 128 sectors per track • 512 bytes/sector • Track -to-track seek time of 10 milliseconds • Rotational speed of 6000 RPM. a. What is the capacity of the drive? b. What is the access time? . ...
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