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How many bits does a RAM with 12-bit address and 10-bit
words have?
Solution
If we have n bits to store an Address then we can have
If n=12 (from the question)
Substitute n=12 in 2n.
Total memory = 212
RAM require 4096 bits.
10-bit words :
If n=10 (from the question)
In this 1word is 2 bytes =2*8=16 bits.
Size of each address * number of addresses = 16 * 2n.
Substitute corrosponding values in the above formula.
Total memory = 16*210
= 16384 bits
RAM require 16384 bits.
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How many bits does a RAM with 12 -bit address and 10-bit words have? Solution 12-bit address : If we have n bits to store an Address then we can have RAM of 2n addresses. If n=12 (from the question) Substitute n=12 in 2n. Total memory = 212 RAM require 4096 bits. 10-bit words : If n=10 (from the question) In this 1word is 2 bytes =2*8=16 bits. Size of each address * number of addresses = 16 * 2n. Substitute corrosponding values in the above formula. Total memory = 16*210 = 16384 bits RAM require 16384 bits. Name: Description: ...
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