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Experiment 3 Poslab

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Subject
Chemistry
School
Palm Beach State College
Type
Homework
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Experiment 3. Intermolecular forces: solutions
Postlab questions
Question 1.
The only insoluble liquids were hexane and water, meaning the hydrogen bonds in water are higher in
energy than in a solution that has interactions between the two solvents. The difference in polarity
between these two compounds accounts for their immiscibility.
Question 2.
All soluble liquids had dipole-dipole interactions or hydrogen bonds, as well as dispersion forces given the
presence of alkane chains. In acetone, the dipole-dipole forces were broken to form new dipole-dipole
bonds between acetone and water. In hexane, the intramolecular dispersion forces were broken to form
new interactions between the alkyl chains of hexane and butanol.
Question 3.
1-butanol and hexane were slightly soluble given that the first is a polar compound with hydrogen bonds
and the latter is an alkane with only dispersion forces. The energy of intramolecular bonds is higher than
the potential intermolecular bonds and therefore they are insoluble in each other.
Question 4.
20 g KNO
3
Question 5.
220 g KNO
3

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Experiment 3. Intermolecular forces: solutions Postlab questions Question 1. The only insoluble liquids were hexane and water, meaning the hydrogen bonds in water are higher in energy than in a solution that has interactions between the two solvents. The difference in polarity between these two com ...
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