# Torque Lab

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User Generated
Subject
Physics
School
Kaplan University
Type
Homework
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TORQUE LAB
Data:
Mass first hanger assembly = 19.81 Mass second hanger assembly = 20.56
Meterstick COM = 50 Meterstick mass = 65.45
PART
Clockwise
PART
Counter Clockwise
First Torque
Second Torque
F
r
τ
total
F
r
τ
F
r
τ
3
19.81
24
475.44
3
20.56
29
596.24
4
119.81
6
718.86
4
65.45
10
654.5
5a
219.81
30
6594.3
5a
65.45
10
654.5
120.56
32
6028
5b
219.81
20
4396.2
5b
65.45
10
654.5
120.56
32
3857.92
Observations part 2:
When the meterstick is not balanced, the meterstick rotates due to the imbalanced
torques. On the other hand, when the meterstick is balanced, despite the differences in the
masses of the objects, it does not move or rotate. The equilibrium is achieved by sliding the
hanging objects on the meterstick.

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Analysis Questions
Part 3-C
1. How many forces are acting on the meterstick when you have it balanced? Identify each.
The four forces acting on the meterstick are the following:
Net force
Weight
Force due to the mass of the first hanger
Force due to the mass of the second hanger
2. Draw a diagram of the meterstick showing each force vector acting on the meterstick. Place
each force in the approximately correct location. Draw and label (CW or CCW) the torque
generated by each force.
3. How many torques are acting on the meterstick when it is balanced? Why is the number of
torques different from the number of forces you identified in question #1?
On a balanced system, two torques are acting on the meterstick. The number of torques is
different from the number of forces mentioned previously because the net force and the weight
will not create a torque since the pivot point serves as the center of rotation for the system.
4. In what direction is each torque acting (clockwise or counterclockwise)?
Since the mass of the second hanger is greater than the mass of the first hanger, the second
torque will rotate in the clockwise direction while the first torque will rotate in the counterclockwise
direction.
5. What is the net torque acting on the meterstick when you have it balanced? How do you know
this by looking at the meterstick?
A balanced meterstick does not have any rotation, which means that the first and second torque
values are equal. Thus, since the net torque follows the equation
𝜏 = 𝜏
1
𝜏
2
, the net torque will
be equal to 0. To figure this out without using equations and by just observing the meterstick, the
meterstick must not move. That is how you know that the system is in equilibrium.
Part 4-B
6. How did you know where to place the hanger assembly in order to make the meterstick
balance?
F
W
F
N
F
1
CCW
F
2
CW

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Unformatted Attachment Preview
TORQUE LAB Data: Mass first hanger assembly = 19.81 Mass second hanger assembly = 20.56 Meterstick COM = 50 Meterstick mass = 65.45 Counter Clockwise Clockwise PART PART F r τtotal 3 19.81 24 475.44 4 119.81 6 5a 219.81 5b 219.81 First Torque Second Torque F r τ 3 20.56 29 596.24 718.86 4 65.45 10 654.5 30 6594.3 5a 65.45 10 20 4396.2 5b 65.45 10 τtotal F r τ 654.5 120.56 32 6028 6682.5 654.5 120.56 32 3857.92 4512.42 Observations part 2: When the meterstick is not balanced, the meterstick rotates due to the imbalanced torques. On the other hand, when the meterstick is balanced, despite the differences in the masses of the objects, it does not move or rotate. The equilibrium is achieved by sliding the hanging objects on the meterstick. Analysis Questions Part 3-C 1. How many forces are acting on the meterstick when you hav ...
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