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MATERIAL BALANCE

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User Generated
Subject
Chemistry
Type
Homework
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n a glycerol plant, a 10% (mass basis) aqueous glycerin solution containing 3% NaCl is treated with butyl alcohol as
illustrated in Figure 4.28. The alcohol fed to the tower contains 2% water on a mass basis. The raffinate leaving the
tower contains all the original salt, 1.0% glycerin and 1.0% alcohol. The extract from the tower is sent to a distillation
column. The distillate from this column is the alcohol containing 5% water.
GLYCERINE
10% * 100LB/HR = 1% in raffinate + 25% in glycerin bottom solution
100lb/hr = 1% in raffinate + 25% in glycerin bottom solution
ALCOHOL
98% * 1000LB/HR = 1% in raffinate + 95% in distillate
980 lb/hr = 1% in raffinate + 95% in distillate
WATER
in raffinate water = 100%-2% - Nacl
= 98%-Nacl
NaCl = 3% * 100LB/HR = 30LB/HR
water in raffinate = 98% -30lb/hr
2% *1000LB/HR + 87% *1000lb/hr = 98% raffinate - 30lb/hr + 5% in alcohol distillate + 75% in glycerin bottom
solution
20lb/hr + 870lb/hr +30lb/hr = 98% raffinate + 5% in alcohol distillate + 75% in glycerin bottom solution

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n a glycerol plant, a 10% (mass basis) aqueous glycerin solution containing 3% NaCl is treated with butyl alcohol as illustrated in Figure 4.28. The alcohol fed to the tower contains 2% water on a mass basis. The raffinate leaving the tower contains all the original salt, 1.0% glycerin and 1.0% alcohol. The extract from the tower is sent to a distillation column. The distillate from this column is the alcohol containing 5% water. GLYCERINE 10% * 100LB/HR = 1% in raffinate + 25% in glycerin bottom solution 100lb/hr = 1% in raffinate + 25% in glycerin bottom solution ALCOHOL 98% * 1000LB/H ...
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