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Solution Of Quadratic Equation

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Running head: Solution for Quadratic Equation Solution for Quadratic Equation Student Name: Instructor Name: Course: Date: 1 Solution for Quadratic Equation 2 1. If x²+4y²=40 and xy = 6, what will be the value of x+2y? Please explain how you arrived at your answer. Solutions If x²+4y²=40 and xy=6, what will be the value of x+2y? Let u = (x + 2y)² Expanding the equation, we obtain, u = (x + 2y)(x + 2y) u = x² + 4xy + 4y² Collecting the like terms together, we have: u = (x² + 4y²) + 4(xy) Substituting the given values, we get: u = 40 + 4*6 u = 40 + 24 u = 64 But u = (x + 2y)² = 64 Square rooting both sides, x + 2y = √64 x + 2y = ± 8 Since x and y are positive real numbers, we can therefore ignore the negative value. Hence our final answer of x+2y will be: 8 Solution for Quadratic Equation 3 Reference Aygün, S., Aktas, C., & Mishra, B. (2018). Quadratic equation of ...
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