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Decomposition Reaction

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Running head: Decomposition reaction 1 Decomposition reaction Student Name: Instructor Name: Course: Date: Decomposition reaction 2 1. At 70 k, CCl4 decomposes to carbon and chlorine. The kp for the decomposition is 0.76. Find the starting pressure of CCl4 at this temperature that will produce a total of 1.0 atm at equilibrium CCl4 ⇌ C(s) + 2Cl2 (g) Solution Let the initial pressure of CCl4 be X and the equilibrium pressure of C(s) be Y CCl4 ⇌ C(s) + 2Cl2 (g) Initial (atm) X 0 C (atm) -Y +2Y E (atm) X-Y +2Y Total pressure at equilibrium = X - Y + 2Y = 1.0 X = 1.0- Y Kp = (Cl2)^2 CCl4 0.76 = (2Y)^2 X−Y (2Y)^2 0.76 = (1−Y)−Y 0.76 = (2Y)^2 1−2Y 0.76(1-2Y) = (2Y)2 Decomposition reaction 3 0.76 - 1.52Y = 4Y2 4Y2+ 1.52Y – 0.76=0 Solving the equation, we obtain the values of Y as follows; Y= 0.2855 or Y = -0.6655 Taking the positive value since pressure can never be negative, the value of Y= 0.2855 Hence the starting pressure of CCl4 will be, X= 1-Y =1-0.2855 = 0.7145 atm Decomposition reaction 4 References Muradov, N., Smith, F., & Ali, T. (2005). Catalytic activity of carbons for methane decomposition reaction. Catalysis Today, 102, 225-23 ...
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