Access over 20 million homework & study documents

search

reaction mechanisms

Subject

Chemistry

Type

Exam Practice

Rating

Showing Page:
1/1
1.
T(KMnO4/CaCO3) = Э CaCO3*N(KMnO4)/1000
N(KMnO4) = 6/100 = 0,06 H
m1/Э1 = N2*V2
m1 = Э1*N2*V2 = 0,01885*0,06 *100 = 0,1131 г
w = 0,1131 г/0,5 = 0,15 г = 0,754(75,4%)
2.
Сr
2
О
7
2-
+ 6I
-
+ 14Н
+
→ 2Сr
3+
+ 3I
2
+ 7Н
2
О,
I
2
+ 2S
2
O
3
2-
→ 2I
-
+ S
4
О
6
2-
.
m Cr = T(Na
2
S
2
O
3
)∙V(N
2
S
2
O
3
)/M(Na
2
S
2
O
3
)∙M(Cr),
T(Na
2
S
2
O
3
) = Э *N(Na
2
S
2
O
3
)/1000
T(Na
2
S
2
O
3
) = 79 *0.02/1000 = 0,00158
m Cr = 0,00158 * 10. 36 / 158,10∙ 52 = 1,99* 10
-6
2Fе
3+
+ 2I
-
= 2Fe
2+
+ I
2
.
T(Na
2
S
2
O
3
) = 79 *0.02/1000 = 0,00158
m Fe = 0,00158* 17,37/158,10∙ 56 = 3,09* 10
-6

Sign up to view the full document!

lock_open Sign Up

Unformatted Attachment Preview

1.T(KMnO4/CaCO3) = ? CaCO3*N(KMnO4)/1000N(KMnO4) = 6/100 = 0,06 Hm1/?1 = N2*V2m1 = ?1*N2*V2 = 0,01885*0,06 *100 = 0,1131 ?w = 0,1131 ?/0,5 = 0,15 ? = 0,754(75,4%)2.?r2?72- + 6I- + 14?+? 2?r3+ + 3I2 + 7?2?,I2 + 2S2O32- ? 2I- + S4?62-.m Cr = T(Na2S2O3)?V(N2S2O3)/M(Na2S2O3)?M(Cr),T(Na2S2O ...
Purchase document to see full attachment
User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service.

Anonymous
Super useful! Studypool never disappoints.

Studypool
4.7
Trustpilot
4.5
Sitejabber
4.4