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Chem01

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Chemistry
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Carrington College
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1) The 250.0 mL solution has 38.2 µg/L of arsenic, so the mass of arsenic is: 38.2 ∙ 10−6 𝑔 𝐿 ∙ 0.25 𝐿 = 9.55 ∙ 10−6 𝑔 Which means that the original rice sample had a mass fraction of arsenic of 9.55 ∙ 10−6 𝑔⁄12.0 𝑔 = 795.8 ∙ 10−9 = 796 𝑝𝑝𝑏 2) Corre ...
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