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Integral

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Question: How to solve the integral of 3sec(2x-1)tan(2x-1)? Answer: integral of 3sec(2x-1)tan(2x-1)dx Let us assume sec(2x-1)=u Taking the derivative of u with respect to x, du/dx=2sec(2x-1)tan(2x-1) ➢ du=2sec(2x-1)tan(2x-1)dx ➢ 1/2du=sec(2x-1)tan(2x-1)dx. ......(1) Using the value from equation ...
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