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STAT200: Assignment #3 - Inferential Statistics Analysis and Writeup
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Assignment #3: Inferential Statistics Analysis and Write-up
Identifying Information
Student (Full Name):
Class:
Instructor:
Date:
Part A: Inferential Statistics Data Analysis Plan and Computation
Introduction:
Variables Selected:
Table 1: Variables Selected for Analysis
Variable Name in the Data Set
Variable Type
Description
Qualitative or
Quantitative
Variable 1: Annual Household Income in
USD
Socioeconomic
Quantitative
Variable 2: Entertainment
Expenditure
Quantitative
Variable 3: Education
Expenditure
Quantitative
Data Analysis:
1. Confidence Interval Analysis: For one expenditure variable, select and run the appropriate method
for estimating a parameter, based on a statistic (i.e., confidence interval method) and complete the
following table (Note: Format follows Kozak outline):
Table 2: Confidence Interval Information and Results
Name of Variable: Education
State the Random Variable and Parameter in Words:
Continuous Random Variable
Confidence interval method including confidence level and rationale for using it:
95% confidence level
State and check the assumptions for confidence interval:
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STAT200: Assignment #3 - Inferential Statistics Analysis and Writeup
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i. Homogeneity of variance is assumed
ii. Normality of assumption is assumed
iii. Each value is independently sampled
Method Used to Analyze Data: Applet
Find the sample statistic and the confidence interval: M=294.97, 95% Cl[225.3522, 364.5878].
Statistical Interpretation: You can be 95% confident that the population mean falls between 225.3522
and 364.5878
2. Hypothesis Testing: Using the second expenditure variable (with socioeconomic variable as the
grouping variable for making two groups), select and run the appropriate method for making decisions
about two parameters relative to observed statistics (i.e., two sample hypothesis testing method) and
complete the following table (Note: Format follows Kozak outline):
Table 3: Two-Sample Hypothesis Test Analysis
Research Question:
Is there any statistical difference between the mean expenditure on entertainment and education
level
Two Sample Hypothesis Test that Will Be Used and Rationale for Using It:
i. The sample size, n=30, therefore, the samples are normally distributed
ii. The sample size from both population groups are independent of each other
State the Random Variable and Parameters in Words:
State Null and Alternative Hypotheses and Level of Significance:
Null hypothesis: The mean expenditure on entertainment and education level is equal.
Alternative hypothesis: There is no difference between the mean expenditure on entertainment and
education level
Method Used to Analyze Data:
Excel
Find the sample statistic, test statistic, and p-value:
Sample statistic= 2.002
Test statistic= -5.164
p-value = 0.0000031
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STAT200: Assignment #3 - Inferential Statistics Analysis and Writeup
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Conclusion Regarding Whether or Not to Reject the Null Hypothesis:
Reject the null hypothesis
Part B: Results Write Up
Confidence Interval Analysis:
A confidence interval is a range that has a likelihood of containing an unknown population mean. At
95% confidence level was carried out on annual household income data using applet software and the
results showed that the interval to be [225.3522, 364.5878. Therefore, the is the interval 95%
confident that the population means falls between 225.3522 and 364.5878.
Two Sample Hypothesis Test Analyses:
A two-sample t-test analysis was carried out on education and entertainment expenditure to
determine whether there exists a significant difference between the means of education and
entertainment expenditure. The sample t-test value was greater than the t critical value hence the
results are significant at alpha=0.05. In addition, the p-value is less than 0.05 hence the results are
statistically significant.
Discussion:
The mean household income was found to be M= 294.97 and results showed that 95% confidence
interval to be [225.3522, 364.5878]. Therefore it can be concluded that we are 955 confident that the
average household expenditure is lies between 225.3522 and 364.5878.
The two-sample t-test results were found to be statistically significant at alpha= 0.05 since the p-value
is less than 0.05. Therefore we reject the null hypothesis and conclude that there exists a significant
difference between the mean expenditure on entertainment and education level.

### Unformatted Attachment Preview

Assignment #3: Inferential Statistics Analysis and Write-up Identifying Information Student (Full Name): Class: Instructor: Date: Part A: Inferential Statistics Data Analysis Plan and Computation Introduction: Variables Selected: Table 1: Variables Selected for Analysis Variable Name in the Data Set Variable Type Description Qualitative or Quantitative Variable 1: Annual Household Income in USD Socioeconomic Quantitative Variable 2: Entertainment Expenditure Quantitative Variable 3: Education Expenditure Quantitative Data Analysis: 1. Confidence Interval Analysis: For one expenditure variable, select and run the appropriate method for estimating a parameter, based on a statistic (i.e., confidence interval method) and complete the following table (Note: Format follows Kozak outline): Table 2: Confidence Interval Information and Results Name of Variable: Education State the Random Variable and Parameter in Words: Continuous Random Variable Confidence interval method including confidence level and rationale for using it: 95% confidence level State and check the assumptions for confidence interval: STAT200: Assignment #3 - Inferential Statistics Analysis and Writeup Page 1 of 4 i. ii. iii. Homogeneity of variance is assumed Normality of assumption is assumed Each value is independently sampled Method Used to Analyze Data: Applet Find the sample statistic and the confidence interval: M=294.97, 95% Cl[225.3522, 364.5878]. Statistical Interpretation: You can be 95% confident that the population mean falls between 225.3522 and 364.5878 2. Hypothesis Testing: Using the second expenditure variable (with socioeconomic variable as the grouping variable for making two groups), select and run the appropriate method for making decisions about two parameters relative to observed statistics (i.e., two sample hypothesis testing method) and complete the following table (Note: Format follows Kozak outline): Table 3: Two-Sample Hypothesis Test Analysis Research Question: Is there any statistical difference between the mean expenditure on entertainment and education level Two Sample Hypothesis Test that Will Be Used and Rationale for Using It: i. The sample size, n=30, therefore, the samples are normally distributed ii. The sample size from both population groups are independent of each other State the Random Variable and Parameters in Words: State Null and Alternative Hypotheses and Level of Significance: Null hypothesis: The mean expenditure on entertainment and education level is equal. Alternative hypothesis: There is no difference between the mean expenditure on entertainment and education level Method Used to Analyze Data: Excel Find the sample statistic, test statistic, and p-value: Sample statistic= 2.002 Test statistic= -5.164 p-value = 0.0000031 STAT200: Assignment #3 - Inferential Statistics Analysis and Writeup Page 1 of 4 Conclusion Regarding Whether or Not to Reject the Null Hypothesis: Reject the null hypothesis Part B: Results Write Up Confidence Interval Analysis: A confidence interval is a range that has a likelihood of containing an unknown population mean. At 95% confidence level was carried out on annual household income data using applet software and the results showed that the interval to be [225.3522, 364.5878. Therefore, the is the interval 95% confident that the population means falls between 225.3522 and 364.5878. Two Sample Hypothesis Test Analyses: A two-sample t-test analysis was carried out on education and entertainment expenditure to determine whether there exists a significant difference between the means of education and entertainment expenditure. The sample t-test value was greater than the t critical value hence the results are significant at alpha=0.05. In addition, the p-value is less than 0.05 hence the results are statistically significant. Discussion: The mean household income was found to be M= 294.97 and results showed that 95% confidence interval to be [225.3522, 364.5878]. Therefore it can be concluded that we are 955 confident that the average household expenditure is lies between 225.3522 and 364.5878. The two-sample t-test results were found to be statistically significant at alpha= 0.05 since the p-value is less than 0.05. Therefore we reject the null hypothesis and conclude that there exists a significant difference between the mean expenditure on entertainment and education level. STAT200: Assignment #3 - Inferential Statistics Analysis and Writeup Page 1 of 4 Name: Description: ...
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