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Physics Problem

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Physics

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Physics Problem
An archer shoots an arrow at a 75 m distant target; the
bull’s-eye of the target is at same height as the release
height of the arrow. If d = 75 m and v = 37 m/s. At what
angle must the arrow be released to hit the bull’s-eye if
its initial speed is 37m/s.
Data:




 !
"
#$%
&'
Soluon:
(%)%%*+
,
"
"&-
#.)/)%01)0

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Physics Problem
,
"
2"&- !
3). !0
452"&
#0450
6 5!!!"67""5775756"&
#(
84
0
9
84
,6 5!!!"67""5775756-"&
# "&" 7"6!64"644"!76!756!!
#"0
&45 "56"665665""657!647
:)%0
&45 "7;
< angle must be equal to 16.24° for the arrow to hit the
bull’s-eye if its initial speed is 37m/s and the distance between
archer and target is 75m. The calculations are done above by
using “9$=)>

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Anonymous
Just what I needed…Fantastic!

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