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# Mathematics : Problem

Mathematics

Study Guide

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QUESTION:



 !
"!
SOLUTION:
#


\$\$\$\$\$%
&!'("!)
*"!'(
+
*+,%)
+


-
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.,!/!!'()
± 0b
2
– 4*a*c) / 2*a …………….3
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.1)
20
345%565%
20476
20%6

204516
2016
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%2016
%2016%
&8,
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-
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91.,
!

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QUESTION: A projectile follows a parabolic path whose height in meters is given by the function f (x) = - x2 + 2x + 2. Find the maximum horizontal distance that the projectile may cover.SOLUTION: As Given function is f(x) = - x2 + 2x + 2 ?????1Where f(x) is the height and "x" is the horizontal distance, thenSo the horizontal distance "x" will be greatest when height f(x) = 0So by putting f(x) = 0 in equation 1, we get 0 = - x2 + 2x + 2Or - x2 + 2x + 2 = 0 ??????2Now we use the quadratic formula to find the distance "x", then ...
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Anonymous
I was struggling with this subject, and this helped me a ton!

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