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Quadratic

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Mathematics
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2𝑡 2 + 3𝑡 − 10 = 0 Here 𝑎 = 2, 𝑏 = 3, 𝑐 = −10 −𝑏 ± √𝑏 2 − 4𝑎𝑐 𝑡= 2𝑎 𝑡= −(3) ± √(3)2 − 4(2)(−10) 2(2) 𝑡= −3 ± √9 + 80 4 𝑡= −3 ± √89 4 (a) Values of N, M and D 𝑁 = −3, 𝐷 = 89, 𝑀 = 4 (b) Solutions. 𝑡= 𝑡= −3 ...
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