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please explain number 8 step by step, thank you For the
following exercises, find the domain of the function. 5, V(x,
y) = 4x2 + y2 6. f(x, y) = N/x2 + y2-4 7, f(x, y) = 4 ln(y2-x) 8.
g(x, y)=1/16-4x2-y2 y +2 f(x, y)\',2- 10,
Solution
Here first we if look into the question 8
g(x,y) = sqrt [16 - 4x2 - y2 ]
so here we can see that the given function is square root
value. So, anything inside it can\'t be less than 0. so,
16 - 4x2 - y2 >= 0
=>
4x2 + y2 <= 16
so that will be the equation of an ellipse. any value under
that ellipse would be the domain of functio g(x,y)
so,
Domain of g : 4x2 + y2 <= 16 where x E (-2,2] & y E [-4,4]
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please explain number 8 step by step, thank you For the following exercises, find the domain of the function. 5, V(x, y) = 4x2 + y2 6. f(x, y) = N/x2 + y2 -4 7, f(x, y) = 4 ln(y2-x) 8. g(x, y)=1/16-4x2-y2 y +2 f(x, y)\',2- 10, Solution Here first we if look into the question 8 g(x,y) = sqrt [16 - 4x2 - y2 ] so here we can see that the given function is square root value. So, anything inside it can\'t be less than 0. so, 16 - 4x2 - y2 >= 0 => 4x2 + y2 <= 16 so that will be the equation of an ellipse. any value under that ellipse would be the domain of functio g(x,y) so, Domain of g : 4x2 + y2 <= 16 where x E (-2,2] & y E [-4,4] Name: Description: ...
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