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Carbonic Acid Solution

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Running head: CARBONIC ACID SOLUTION 1 Carbonic Acid Solution Author Author Affiliation CARBONIC ACID SOLUTION Question How many milliliters of 60% carbonic acid must be mixed with how many milliliters of 15% carbonic acid to make 650 milliliters of a 38% carbonic acid solution? Please explain how you arrived at your answer Solution: The concentration of a solute= amount of solute / volume of solution (Mania et al., 2018). c=n/v (1) The total amount of solute before and after the dilution remains the same. Rearranging; n=c×v (2) Set up two simultaneous equations from the information given. We get two equations and two unknowns in order to solve it. From (2) we can write: (60×V60)+(15×V15)=650×38 ∴60V60+V15=24,700 (3) Where V60 and V15 refer to the volumes of the 60% and 15% solution respectively Using the percentage (%) as the concentration 2 CARBONIC ACID SOLUTION Since we know the total volume we can write: V60+V15=650 (4) So (3) and (4) are our simultaneous equations. Rearranging (4)⇒ V60=650−V15 We can now substitute this value for V60 back into (3)⇒ 60(650−V15)+15V15=24,700 ∴39,000−60V15+15V15=24,700 ∴60V15−15V15=39,000−24,7000 ...
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