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Logarithms

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LOGARITHMS 1 Logarithms Student’s Name Institutional Affiliation LOGARITHMS Solve log ( 2x + 1 ) – log 6 = 2 for x. Solution Logarithms law ; Log A – Log B =Log(A/B) Therefore; Log(2x+1) – Log 6 = Log((2x+1)/6) Then Log((2x+1)/6)=log(102) Divide both side by log base 10 This gives (2x+1)/6=102 2x+1=100*6 2x +1=600 Subtract 1 on both sides 2x=600 - 1 2x = 599 Divide both sides by 2 X= 299.5 2 Name: Logarithms Description: Logarithms law ; Log A ? Log B =Log(A/B) ...
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