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pseudocode divide and conquer largest and smallest

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Computer Science
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algorithm largestSmallest(numbers[1..n]) -> (smallest, largest) begin if (n == 1) return (A[1], A[1]) else if (n == 2) if( A[1] < A[2]) return (A[1], A[2]) else return (A[2], A[1]) else (largest_left, smallest_left) = largestSmallest(A[1...(n/2)]) (largest_right, smalle ...
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