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1/1
{1/2, 1/4, 1/6, 1/8, 1/10, ...}
a sub n = ?
Solution
The given terms of the series are: 1/2,
1/4, 1/6, 1/8, 1/10 1/12, 1/14, 1/16 ... Thus Term
number 1 = 1/2 = 1/(1*2) Term number 2 = 1/4 1/(2*2)
Term number 3 = 1/6 = 1/(3*2) Term number 4 = 1/8 =
1/(4*2) Term number 5 = 1/10 = 1/(5*2) Term number 6
= 1/12 = 1/(6*2) Term number 7 = 1/14 = 1/(7*2) Term
number 8 = 1/16 = 1/(8*2) Term number n = 1/(n*2)
Answer: nth term = 1/(n*2

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{1/2, 1/4, 1/6, 1/8, 1/10, ...} a sub n = ? Solution The given terms of the series are: 1/2, 1/4, 1/6, 1/8, 1/10 1/12, 1/14, 1/16 ... Thus Term number 1 = 1/2 = 1/(1*2) Term number 2 = 1/4 1/(2*2) Term number 3 = 1/6 = 1/(3*2) Term number 4 = 1/8 = 1/(4*2) Term number 5 = 1/10 = 1/(5*2) Term number 6 = 1/12 = 1/(6*2) Term number 7 = 1/14 = 1/(7*2) Term number 8 = 1/16 = 1/(8*2) Term number n = 1/(n*2) Answer: nth term = 1/(n*2 Name: Description: ...
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