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# The sum of 5 consecutive integers is 12 more than 4 times the 4th integer what I are the numbers

Algebra

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Question:
The sum of 5 consecutive integers is 12 more than 4 times the 4th
integer what I are the numbers
Consecutive numbers are separated by 1. For example, 1, 2 are all consecutive numbers because the
difference between them is 2-1 = 1.
We can let the 5 consecutive numbers be: x, x+1, x+2, x+3, x+4
Now, we set up an equation that describes the world problem. Let's start with the left.
Mathematically, "the sum of 5 consecutive numbers" is x + x+1 + x+2 + x+3 + x+4 = 5x+10
The next part of the problem "is 12 more than 4 times the 4th integer."
Mathematically, "is" means "equals." "12 more than 4 times the 4th integer" means "12+4(x+3)
Now, set up the equation:
5x+10 = 12+4(x+3)
Distribute the 4 to the (x+3):
5x+10 = 12+4x+12
5x+10 = 4x+24
Gather the x terms on one side:
(5x-4x)+10 = 24
x + 10 = 24
x = 14
The numbers: 14, 15, 16, 17, 18

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Question:The sum of 5 consecutive integers is 12 more than 4 times the 4th integer what I are the numbersAnswer:Consecutive numbers are separated by 1. For example, 1, 2 are all consecutive numbers because the difference between them is 2-1 = 1.We can let the 5 consecutive numbers be: x, x+1, ...
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