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20171010062546exp 3 Free Fall Gravity Data Typed 1

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Subject

Physics

Type

Homework

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zvpunrynerara984

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Free Fall Experiment:

Data Table

1) I need a step by step calculation for the data table above (Avg

time, Avg time^2, Velocity) show the work below.

2) I also need: Vy, Vy^2

The solution should be type..

1. For trial 1,

Time 1 = 0.4657 s, Time 2 = 0.4750 s

Therefore, Avg time = (0.4657+0.4750)/2 = 0.4704

Avg time^2 = (0.4704 * 0.4704) = 0.2213

Velocity = (1/0.4704) = 2.1259

Vy = -gt = -8.6924*0.4704 = - 4.089

Vy^2 = 16.72

2. Trial 2,

Avg time = (Time 1+Time 2)/2 = (0.4367+0.4346)/2 = 0.4357

Avg Time^2 = (0.4357*0.4357) = 0.1898

Velocity = (0.85/0.4357) = 1.9509

Vy = -gt = -8.6924*0.4357 = -3.79

Vy^2 = 14.3641

Trials

Vertical Dist

Time 1

Time 2

Avg Time

Velocity

1.0 m

0.4657 s

0.4750 s

0.4704

0.2213

2.1259

0.85 cm

0.4367 s

0.4346 s

0.4357

0.1898

1.9509

0.725 cm

0.3977 s

0.3956 s

0.3967

0.1574

1.8276

0.65 cm

0.3756 s

0.3780 s

0.3768

0.1420

1.7251

0.56 cm

0.3647 s

0.3476 s

0.3562

0.1269

1.5722

Exp Gravity Accel: 8.6924

% Error:

11.30

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3. Trial 3,

Avg time = (Time 1+Time 2)/2 = (0.3977+0.3956)/2 = 0.3967

Avg Time^2 = 0.3967*0.3967 = 0.1574

Velocity = 0.725/0.3967 = 1.8276

Vy = -gt = -8.6924*0.3967 = -3.44

Vy^2 = 3.44*3.44 = 11.833

4. Trial 4,

Avg time = (Time 1+Time 2)/2 = (0.3756+0.3870)/2 = 0.3768

Avg Time^2 = 0.3768*0.3768 = 0.1420

Velocity = 0.65/0.3768 = 1.7251

Vy = -gt = -8.6924*0.3768 = -3.275

Vy^2 = 3.275*3.275 = 10.725

5. Trial 5,

Avg time = (Time 1+Time 2)/2 = (0.3647+0.3746)/2 = 0.3562

Avg Time^2 = 0.3562*0.3562 = 0.1269

Velocity = 0.56/0.3562 = 1.5722

Vy = -gt = -8.6924*0.3562 = -3.097

Vy^2 = 3.097*3.097 = 9.60

1) Choose two points and find the slope.

-v

-t

(2.1259-1.5722)/(0.4750-0.3476)

0.5537/0.1274

4.3462

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Free Fall Experiment: Data Table Avg Time 0.4704 Avg Time2 0.2213 Velocity 0.4657 s Time 2 0.4750 s 0.85 cm 0.4367 s 0.4346 s 0.4357 0.1898 1.9509 3 0.725 cm 0.3977 s 0.3956 s 0.3967 0.1574 1.8276 4 0.65 cm 0.3756 s 0.3780 s 0.3768 0.1420 1.7251 5 0.56 cm 0.3647 s 0.3476 s 0.3562 0.1269 1.5722 Trials 1 Vertical Dist 1.0 m 2 Time 1 Exp Gravity Accel: 8.6924 2.1259 % Error: 11.30 1) I need a step by step calculation for the data table above (Avg time, Avg time^2, Velocity) show the work below. 2) I also need: Vy, Vy^2 The solution should be type.. 1. For trial 1, Time 1 = 0.4657 s, Time 2 = 0.4750 s Therefore, Avg time = (0.4657+0.4750)/2 = 0.4704 Avg time^2 = (0.4704 * 0.4704) = 0.2213 Velocity = (1/0.4704) = 2.1259 Vy = -gt = -8.6924*0.4704 = - 4.089 Vy^2 = 16.72 2. Trial 2, Avg time = (Time 1+Time 2)/2 = (0.4367+0.4346)/2 = 0.4357 Avg Time^2 = (0.4357*0.4357) = 0.1898 Velocity = (0.85/0.4357) = 1.9509 Vy = -gt = -8.6924*0.4357 = -3.79 Vy^2 = 14.3641 3. Trial 3, Avg time = (Time 1+Time 2)/2 = (0.3977+0.3956)/2 = 0.3967 Avg Time^2 = 0.3967*0.3967 = 0.1574 Velocity = 0.725/0.3967 = 1.8276 Vy = -gt = -8.6924*0.3967 = -3.44 Vy^2 = 3.44*3.44 = 11.833 4. Trial 4, Avg time = (Time 1+Time 2)/2 = (0.3756+0.3870)/2 = 0.3768 Avg Time^2 = 0.3768*0.3768 = 0.1420 Velocity = 0.65/0.3768 = 1.7251 Vy = -gt = -8.6924*0.3768 = -3.275 Vy^2 = 3.275*3.275 = 10.725 5. Trial 5, Avg time = (Time 1+Time 2)/2 = (0.3647+0.3746)/2 = 0.3562 Avg Time^2 = 0.3562*0. ...
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