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Math Question 2

Content type
User Generated
Subject
Mathematics
Type
Homework
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In order to solve this problem, you have to understand these concepts: factoring
polynomials, using the FOIL method in multiplying binomials and determining possible
factors of real numbers.
Given: x
2
+ 4y
2
= 40
xy = 6
Required: Value of x + 2y
Solution:
In order to get the value of "x + 2y", solve for the values of "x" and "y". Since there are
two equations given and two unknown variables, it is possible to determine the values of
"x" and "y".
Step 1: Using the equation "xy=6", solve for the value of "y" in terms of "x" by dividing
both sides of the equation by "x"
(xy)/x = 6/x
y=6/x
Step 2: Using the equation "x
2
+ 4y
2
= 40", substitute "y=6/x". Resulting equation would
be:
x
2
+ 4(6/x)
2
= 40
Step 3: Expand the equation
x
2
+ 4(6
2
/ x
2
) = 40
x
2
+ 4(36 / x
2
) = 40
x
2
+ (144 / x
2
) = 40
Step 4: Simplify the equation by removing fractions. In this case we have to remove "x
2
"
by multiplying both sides of the equation by "x
2
"
(x
2
) [x
2
+ (144 / x
2
)] = (40) (x
2
)

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x
4
+ 144 = 40x
2
Step 5: Place all parts of the equation on one side, then arrange every term from
highest to lowest degree of exponents to easily factor the polynomial
x
4
- 40x
2
+144 = 0
The resulting polynomial is a 4th degree polynomial. To simplify things,
Let u = x
2
, resulting equation would be
u
2
- 40u +144 = 0 (I simply used "u" to represent "x
2
" in order to easily factor the
polynomial)
Step 6: Factor "u
2
- 40u +144 = 0"
Remember the FOIL (FIRST, OUTSIDE, INSIDE, LAST) Method: (x+a)(x+b) = x
2
+ bx +
ax + ab
By reversing the FOIL Method, you'll come up with 2 factors.
In our equation: u
2
- 40u +144 = 0
Look for factors of "u
2
", then look for possible factors of "+144" that would result to "-40"
when added. Resulting factors would be "-36" and "-4"
Reversing the FOIL Method would give us:
(u-36)(u-4) = 0
Step 7: Find the values of "u" using zero product rule. When ab=0, a=0 / b=0, therefore
we can equate both factors by 0 in order to get the values of "u"
u-36=0 ; u-4=0
u=36 u=4
Step 8: Remember that "u = x
2
", therefore
x
2
= 36; x = +6 and -6

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In order to solve this problem, you have to understand these concepts: factoring polynomials, using the FOIL method in multiplying binomials and determining possible factors of real numbers. Given: x2 + 4y2 = 40 xy = 6 Required: Value of x + 2y Solution: In order to get the value of "x + 2y", solve for the values of "x" and "y". Since there are two equations given and two unknown variables, it is possible to determine the values of "x" and "y". Step 1: Using the equation "xy=6", solve for the value of "y" in terms of "x" by dividing both sides of the equation by "x" (xy)/x = 6/x y=6/x Step 2: Using the equation "x2 + 4y2 = 40", substitute "y=6/x". Resulting equation would be: x2 + 4(6/x)2 = 40 Step 3: Expand the equation x2 + 4(62 / x2) = 40 x2 + 4(36 / x2) = 40 x2 + (144 / x2) = 40 Step 4: Simplify the equation by removing fractions. In this case we have to remove "x2" by multiplying both sides of the equation by "x2" (x2) [x2 + (144 / x2)] = (40) (x2) x4 + 144 = 40x2 Step 5: Place all parts of the equation on one side, then arrange every term from highest to lowest degree of exponents to easily factor the polynomial x4 - 40x2 +144 = 0 The resulting polynomial is a 4th degree polynomial. To simplify things, Let u = x2, resulting equation would be u2 - 40u +144 = 0 (I simply used "u" to represent "x2" in order to easily factor the polynomial) Step 6: Factor "u2 - 40u +144 = 0" Remember the FOIL (FIRST, OUTSIDE, INSIDE, LAST) Method: (x+a)(x+b) = x2 + bx + ax + ab By reversi ...
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