Access Millions of academic & study documents

Simplify By Using The Distributive Property

Content type
User Generated
Subject
Algebra
Type
Homework
Showing Page:
1/7
Simplify by using the distributive property
1. (2x + 1)(x - 6)
Solution:
distribute parenthesis using : (a + b) (c + d) = ac + ad + bc + bd
a = 2x, b =1, c = x, d = -6
= 2x x + 2x ( - 6) + 1 x + 1 (-6)
apply minus- plus rules: +(-a ) = - a
= 2xx - 2x 6 + 1 x -1 6
= 2x
2
- 11x - 6
2. (2y - 3)(y + 2)
Solution:
distribute parenthesis using : (a + b) (c + d) = ac + ad + bc + bd
a = 2y, b =-3, c = y, d = 2
= 2y y + 2y 2 - 3 y - 3 2
= 2yy + 2y 2 -3 y - 3 2
= 2y
2
+y - 6
3. (5y - 2)(3y - 1)
Solution:
distribute parenthesis using : (a + b) (c + d) = ac + ad + bc + bd
a = 5y, b =-2, c = 3y, d = -1
= 5y 3y + 5y (-1) -2 3y - 2 (-1)
apply minus- plus rules: - (-a ) = -a
= 5y 3y - 5y 1 -2 3y + 2 1

Sign up to view the full document!

lock_open Sign Up
Showing Page:
2/7
= 15y
2
- 11y + 2
4. (5z + 1)(5z -1)
Solution:
distribute parenthesis using : (a + b) (a - b)= a
2
- b
2
a =5z, b =1
= (5x)
2
- 1
2
= 25z
2
- 1
5. (2x + 3)(2x + 3)
Solution:
apply exponent rule: a
b
a
c
= a
b+c
(2x + 3)(2x + 3) = (2x + 3)
1+1
= (2x + 3)
2
6. (x + y)(x + y)
Solution:
apply exponent rule: a
b
a
c
= a
b+c
(x + y)(x + y) = (x + y)
1 + 1
= (x + y)
2
7. (a - b)(a - b)
Solution:
apply exponent rule: a
b
a
c
= a
b+c
(a - b)(a - b) = (a - b)
1 + 1
= (a - b)
2

Sign up to view the full document!

lock_open Sign Up
Showing Page:
3/7

Sign up to view the full document!

lock_open Sign Up
End of Preview - Want to read all 7 pages?
Access Now
Unformatted Attachment Preview
Simplify by using the distributive property 1. (2x + 1)(x - 6) Solution: distribute parenthesis using : (a + b) (c + d) = ac + ad + bc + bd a = 2x, b =1, c = x, d = -6 = 2x • x + 2x ( - 6) + 1 • x + 1 • (-6) apply minus- plus rules: +(-a ) = - a = 2xx - 2x • 6 + 1 • x -1 • 6 = 2x2 - 11x - 6 2. (2y - 3)(y + 2) Solution: distribute parenthesis using : (a + b) (c + d) = ac + ad + bc + bd a = 2y, b =-3, c = y, d = 2 = 2y • y + 2y • 2 - 3 • y - 3 • 2 = 2yy + 2y • 2 -3 y - 3 • 2 = 2y2 +y - 6 3. (5y - 2)(3y - 1) Solution: distribute parenthesis using : (a + b) (c + d) = ac + ad + bc + bd a = 5y, b =-2, c = 3y, d = -1 = 5y • 3y + 5y (-1) -2 • 3y - 2 (-1) apply minus- plus rules: - (-a ) = -a = 5y • 3y - 5y • 1 -2 • 3y + 2 • 1 = 15y2 - 11y + 2 4. (5z + 1)(5z -1) Solution: distribute parenthesis using : (a + b) (a - b)= a2- b2 a =5z, b =1 = (5x)2 - 12 = 25z2 - 1 5. (2x + 3)(2x + 3) Solution: apply exponent rule: ab • ac = ab+c (2x + 3)(2x + 3) = (2x + 3)1+1 = (2x + 3)2 6. (x + y)(x + y) Solution: apply exponent rule: ab • ac = ab+c (x + y)(x + y) = (x + y)1 + 1 = (x + y)2 7. (a - b)(a - b) Solution: apply exponent rule: ab • ac = ab+c (a - b)(a - b) = (a - b)1 + 1 = (a - b)2 8. (a + b)(a + b) Solution: apply exponent rule: ab • ac = ab+c (a + b)(a + b) = (a + b)1 + 1 =(a + b)2 9. (a + 2b)(a + 3b) Solution: distribute parenthesis using : (a + b) (c + d) = ac + ad + bc + bd a = a, b =2b, c = a, d = 3b = a • a + a • 3b + 2b • a + ...
Purchase document to see full attachment
User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service.
Studypool
4.7
Indeed
4.5
Sitejabber
4.4