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ALGEBRA ALGEBRA 1 1 1 7. If x- = 5, then find the value of x4 + x3 X -- х х = 64 4 79 (1) 727 (3) 722 (2) 772 (4) 277 --3xxx+(2-1) = **-*-(x-) = x3 1 3 = 64 X X Sol. (1): (x-1)=5 = 5 1 х → 73 3 x 4 = 64 +3 Squaring both sides, 1 x3 = 64 + 12 = 76 = (5)2 х 1 1 1 10. If x + = *** -2xxx = 25 () + x2 х = 2, then find the value of x3 + 1 x3 (2) 4 (4) 16 -; ܀ ܐܨܒ x 1 = 25 + 2 = 27 (1) 2 (3) 8 1 Squaring both sides again Sol. (1) (x + 1) = 2 . = х 1 (x+ = (27) Cubing both sides, +2 3 1 1 1 X +- + xx +2xx2x x2 = = 729 (2) t .4 1 + 4 х + 2 = 729 Det er for 1 x3 + 1 1 X + - х X = 8 1 x + 3+3xxx} (x + 1) = = x++ -4 + 729-2 1 . 73 + 3x2 = 8 -s stod one 4 1 ...
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