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ALGEBRA E ALGEBRA 22x + 30-22x + 36 llx-18 x2 + 7x +12 x2 + 3x + 2 x + 3 X +7 66 2. 4 + X-1 X-2 11x-18 x(x + 3) +2_*(x + 7) +12 X + 3 X +7 - 66 2(x - 2)+ 4(x - 1) (x - 1)(x-2) а 11x -18 X + 2 12 =X+ x + 3 X +7 [Iatba ta] = с 2x - 4 + 4x -4 x2 - 3x + 2 66 llx-18 2 12 x + 3 x +7 ► 12 (x + 3) = 2 (x + 7) 12x + 36 = 2x + 14 12x-2x= -36 + 14 - 10x=-22 6x -8 66 3 x2 – 3x + 2 llx-18 (6x - 8) (11x- 18) = 66 (x - 3x + 2) = 66x - 196x + 144 = 66x2 - 198x + 132 198x, 196x= 132-144 od 2x = - 12 .. X=-6 -22 10 -11 1 = -2 5 5 SOLVED EXAMPLES BASED ON COMPETITIVE EXAMS 7 1. If 7 + 14 = 1 7x 2 = then what will be the value of х X-7 x-2 5. If + 2, then x= ? X-3 X-9 (1)-5 (2) 5 (3)4 (4)-4 X-7 X-2 + -2 = 0 X-3 X-9 E x2 1 + ? 4 x2 Sol. (1) (1) 5 7 *-3-1+*=2-1=0 X2 1+ X9 = (2) 15 (3) 7 (4) 17 Sol. (1) This question is fundamentally based on for- mula (a + b)2 = a? + b2 + 2ab. Only need is to change the form of the given expression. Let's X-7-x+3 x-2-x+9 -n ...
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