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ALGEBRA ALGEBRA x-62 с + = + + - + + 22. If a (a + 2) = a + b + c; b (b + 2) = a + b + c and c(c + 2) = a + b + c then the value of 1 1 1 a + 2 b + 2 C + 2 (1) 1 (2) 2 (3)-1 (4) 0 Sol. (1) a (a + 2) = a + b + c a+b+c a+2= 1 [Btc + + to] - 2 x-a2 x-c2 1+ -1+ .-1=0 62 +62 +962 +a? a² + b2 x-a2-62-c? x-62-c2-a? *-c2-a?- 62 = 0 b2 +c2 c2 + a2 a? + b2 1 =(x-a? - b? - 62 +62 +2 +a?' a+b? + = 0 ** x-a? - b2 - 2 = 0 x= a + b + c x + a x + b X+C 20. If + + +3 = 0, then the value of b+c C + a a + b 2x is: (1) a+b+c (2) - (a + b + c) w (3) Ja+b+c (4) a² + b + c2 + a od esdal a +2 α a + b + c с Similarly, 1 b + 2 b 1 a+b+c' C+2 a+b+c 1 1 1 + + a + 2 b + 2 C+2 Sol. (2) X + a x+b X+C +1+ +1+ +1= 0 b+c C + a a + b a b + a+b+c a+b+c cu se te a+b+c = 3 x+a+b+c, x+b+c+a X + C + a + b + + = 0 b+c C+a a + b a+b+c = 1 a+b+c )- = 0 1 1 1 (x + a + b + c) + + btc C + a a + b = (x + a + b + c) = 0 x=-(a + b +c) 09 1 23. If x-- х = 5, then the value of 2(x2 is : 2 2 2 (1) 10/29 (2) 5/29 一 ...
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