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a = 5/5 bo titik (60), (2.0),dan (1,5). 12,0 f(x) = ax² + bx to slutat mososlay maka ! f(6)=0 a(6) + 6(6)tc 36a +6b to = -36a-bb bausand + (1 os al b;841) $4221- bi-8 + x + xor st (old tolo 8 (-36a-6b of our - C-36(1) -6 1-8) 384 2.-36 +48 + xoay C = 12:2 a If(2)=0 a (2)² + b(2) te=0 4 a + 2b + c =0 4 at 26-36a-6b=0 -320 4b =0 F(x) = ax²+bx+cestidora ...
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Really useful study material!

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