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19-25 6 18.5 12 6 » cfь P3o class f30 LB b) solve for P30 Pri = LB + Р KN cfo 100 fPk į . 6 (30)(30) 100 P3o - 18.5 + 6 7 19 61 P30 = = 18.5 + 7 6 16 P30 = 18.5 + 7 P30 22 Therefore, 30% of the group of students have less than 22 reactions. WHAT'S MORE . மே மேகமே பானம் ...
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