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Problem Problem 47 20 277 Find exact value of tan(165°) Simplify sin (19)cos(37)+cos( 47 )sin(37) F Since sin AcosB+cos AsinB =sin( A+B), we have = 477 sin (45.)cos(27)+ 47 + cos 5 sin (27) Since tan(A+B) tan A+tan B we can find two values on the 1-tan Atan B Unit Circle whose sum is 165°: 120° and 45°: tan 120+tan45 tan(165)=tan(120+45) 1-tan120)(tan 45) - 5+1 1-13 1-(-V3)(1) 1+ 15 41 21 =sin —+ = sin 7 387 35 = 7 Find the exact value of cos 12 Simplify 57 tan - tan 12 4 57 1+tan 4 12 tan Divide up 11 into two fractions that can be found on 12 the Unit Circle: 4л Зл 12 12 12 4 COS (H)- =COS =COS Since tan A-tanB 1+tan Atan B tan(A-B), we have ...
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