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24 الأعداد . أي عدد يقسم على 2 إذا كان أحاده (، 2، 64 ،8 أي عدد يقسم على 5 إذا كان احاده 0 أوة • أي عدد يقسم على 10 إذا كان احاده ) . وهذا الشي الوحيد الذي يمتد بسهولة إلى اختبارات قابلية القسمة ل (10، 1000، وهكذا. قابلية القسم على 3 9 9 Divisibility by 3 and العدد الصحيح يقبل القسمة على 3 إذا ما كان مجموع الأرقام المكونة للعدد من مضاعفات 3. لذلك 123 قابلة للقسمة على 3 لأن 13 12 ، 6 من مضاعفات 3 ولكن 235 لا تقبل القسمة على 3 حيث 10=2315 و10 لبست من مضاعفات 3. وهذه الخدعة تعمل لأن الأعداد تكتب ک xyz حيث يمكن كتابته على صورة + 100X 10Y+Z وهذا يساوي 2+y + +y و x 99 . والآن البديهي أن 9y+99x بالتأكيد تقبل القسمة على 3، وبذلك يكون العدد الصحيح يقبل القسمة على 3، إذا، وإذا : أوان :-.1 ...
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