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Algebra Answer

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Question
For three consecutive years, Sam invested some money at the start of the year. The first year, he
invested x dollars. The second year, he invested $2,000 less than 5/2 times the amount he invested the first
year. The third year, he invested $1,000 more than 1/5 of the amount he invested the first year.
During the same three years, Sally also invested some money at the start of every year. The first year, she
invested $1,000 less than 3/2times the amount Sam invested the first year. The second year, she invested
$1,500 less than 2 times the amount Sam invested the first year. The third year, she invested $1,400 more
than 1/4 of the amount Sam invested the first year.
If Sam and Sally invested the same total amount at the end of three years, the amount Sam
invested the first year is $ and the amount Sally invested the last year is $
.
Answer
Sam
1
st
year : x
2
nd
year: 5/ 2 x - 2000
3
rd
year: 1/5 x + 1000
Total = x + 5/2x 2000 + 1/5 x + 1000
Total = x + 5/2x +1/5 x - 2000 + 1000
Total = 37/10 x - 1000
Total = 3.7x - 1000
Total sally = Total sam
3.75x 1100 = 3.7x 1000
3.75x 3.7 = 1100 1000
0.05x = 100
X= 100/ 0.05
X= 2000
In first year Sam invested x = $2000
Sally
1
st
year : 3/2 x - 1000
2
nd
year: 2 x - 1500
3
rd
year: 1/4 x + 1400
Total = 3/2 x 1000 + 2 x - 1500 + ¼ x + 1400
Total = 3/2x + 2x +1/4 x - 1000 - 1500 + 1400
Total = 15/4 x - 1100
Total = 3.75x - 1100

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Question For three consecutive years, Sam invested some money at the start of the year. The first year, he invested x dollars. The second year, he invested $2,000 less than 5/2 times the amount he invested the first year. The third year, he invested $1,000 more than 1/5 of the amount he invested the first year. During the same three years, Sally also invested some money at the start of every year. The first year, she invested $1,000 less than 3/2times the amount Sam invested the first year. The second year, she invested $1,500 less than 2 times the amount Sam invested the first year. The third ...
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