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Chemistry

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Chemistry
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The first thing to do here is use the volume by volume percent concentration, %v/v, of the target
solution to determine how many liters of solute, which in your case is sulfuric acid, H2SO4, it
must contain.
A 29% v/v sulfuric acid solution will contain 29 L of sulfuric acid for every 100 L of solution,
which means that your solution must contain
600L solution29 L H2SO4100L solution=174 L H2SO4
Now, let's assume the x represents the volume of the 70% v/v sulfuric acid solution and y
represents the volume of the 25% v/v sulfuric acid solution.
The first equation that you can write here will be
x+y=600 L (1)
This simply uses the fact that the two solutions must be mixed together to form a total volume of
600 L.
Now, use the given percent concentrations to figure out how many liters of sulfuric acid you'd
get in those two solutions
xaL solution70 L H2SO4100L solution=710xaL H2SO4
yaL solution25 L H2SO4100L solution=14yaL H2SO4
This means that you can write
710x+14y=174 L (2)
This equation describes the fact that the amount of sulfuric acid you get from the two solutions
you're mixing must add up to give 174 L.
Use equation (1) to get
x=600−y
Plug this into the second equation to get
710(600−y)+y4=174
420−710y+y4=174
−920y=−246y=547
This means that you have

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The first thing to do here is use the volume by volume percent concentration, %v/v, of the target solution to determine how many liters of solute, which in your case is sulfuric acid, H2SO4, it must contain. A 29% v/v sulfuric acid solution will contain 29 L of sulfuric acid for every 100 L of solution, which means that your solution must contain 600L solution⋅29 L H2SO4100L solution=174 L H2SO4 Now, let's assume the x represents the volume of the 70% v/v sulfuric acid solution and y represents the volume of the 25% v/v sulfuric acid solution. The first equation that you can write here will ...
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Anonymous
Really helpful material, saved me a great deal of time.

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