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Assignment 2

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Subject
Management
School
Saudi electronic university
Type
Homework
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Running head: Assignment 2 1
Assignment 2
Course Name:
Student’s Name:
Course Code:
Student’s ID Number:
Semester: I
CRN:
Academic Year: 1440/1441 H

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Assignment 2 2
QUESTION ONE
A. Determine the mean proportion detective, the UCL and LCL
To calculate UCL and LCL,
Mean= sum of all sample data/12
(0.01+0.03+0.04+0.0+0.01+0.01+0.00+0.01+0.02+0.02+0.03+0.03)/12=0.0175
SD= square root of Variance
Standard deviation=
S=
^2
N
Where is the mean
N is the total data
x is specific data entry
((0.01-0.0175^2)*4 + (0.04-0.0175^2)+ (0.03-0.0175^2)*3+(0.0-0.0175^2)*2+(0.02-
0.0175^2)*2
12
0.000225+0.00050625+0.00046875+0.0006125+0.0000125/12
=0.00015208333
0.00015208333
=0.0123
UCL= Mean+ (3 *SD) = 0.0175+ (3*0.0123) = 0.0544.

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Running head: Assignment 2 1 Assignment 2 Course Name: Student’s Name: Course Code: Student’s ID Number: Semester: I CRN: Academic Year: 1440/1441 H Assignment 2 2 QUESTION ONE A. Determine the mean proportion detective, the UCL and LCL To calculate UCL and LCL, Mean= sum of all sample data/12 (0.01+0.03+0.04+0.0+0.01+0.01+0.00+0.01+0.02+0.02+0.03+0.03)/12=0.0175 SD= square root of Variance Standard deviation= ∣ 𝑥 − µ ∣^2 S=√∑ N Where µ is the mean N is the total data x is specific data entry ((0.01-0.0175^2)*4 + (0.04-0.0175^2)+ (0.03-0.0175^2)*3+(0.0-0.0175^2)*2+(0.020.0175^2)*2 12 0.000225+0.00050625+0.00046875+0.0006125+0.0000125/12 =0.00015208333 √0.00015208333 =0.0123 UCL= Mean+ (3 *SD) = 0.0175+ (3*0.0123) = 0.0544. Assignment 2 3 LCL= mean-(3*SD) = 0.0175-(3*0.0.0123) = -0.0194 B. Draw a control chart and plot each of the sample measurements in it Chart Title 0.07 0.045 0.06 0.04 0.05 0.035 0.04 0.03 0.03 0.025 0.02 0.02 0.01 0.015 0 -0.01 1 2 3 4 5 6 7 8 9 10 11 12 0.01 -0.02 0.005 -0.03 0 UCL LCL sample Data C. Does it appear that the process of making cars is statistically controlled? The process of making tees in this company is out of statistical control since some limits are beyond the LCL and UCL. QUESTION TWO a. Forecast demand for week 7 using five period moving mean. F7= D6+D5+D4+D3+D2 5 Where D= demand in certain week Assignment 2 524+561+738+511+600=2934 2934/5= 586.8 b. Forecast the ...
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