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Honey

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Business
School
Barstow Community College
Type
Homework
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Running Head: HONEYCOMBING
HONEYCOMBING
Student’s Name:
Institution’s Affiliation:

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HONEYCOMBING 2
Given the following information:
Pallet width -4.50’
Clearance between pallets -0.25’
Pallet length -5.00’
Case height -3.00’
Number of ties high of cases per pallet -2 Tiers
Wooden pallet height -0.50’
Number of pallet positions high 3
Space above each pallet for racking system 1.00’
Honeycombing is 15% allowance with 20 cases on each pallet
Question: Calculate the cubic feet needed for a bay height to product; then include
honeycombing. Show work, round answers.
Method
[(4.50’ + 0.25’) (5.00’)] {[(3’) (2’)] + 0.50’ + 1.00’} {3} =?
[4.75 * 5] {[6] + 0.50 + 1.00} {3}
23.75 * [7.50 * 3]
23.75 * 22.50’
Answer

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Running Head: HONEYCOMBING HONEYCOMBING Student’s Name: Institution’s Affiliation: HONEYCOMBING Given the following information: • Pallet width -4.50’ • Clearance between pallets -0.25’ • Pallet length -5.00’ • Case height -3.00’ • Number of ties high of cases per pallet -2 Tiers • Wooden pallet height -0.50’ • Number of pallet positions high – 3 • Space above each pallet for racking system – 1.00’ • Honeycombing is 15% allowance with 20 cases on each pallet Question: Calculate the cubic feet needed for a bay height to product; then include honeycombing. Show work, round answers. Method [(4.50’ + 0.25’) (5.00’)] {[(3’) (2’)] + 0.50’ + 1.00’} {3} =? [4.75 * 5] {[6] + 0.50 + 1.00} {3} 23.75 * [7.50 * 3] 23.75 * 22.50’ Answer 2 HONEYCOMBING 534.375 = 535 cu. Ft (Bledsoe, 2017) Given the following information: • Pallet width -4.50’ • Clearance between pallets -0.25’ • Pallet length -5.00’ • Case height -3.00’ • Number of ties high of cases per pallet -2 Tiers • Wooden pallet height -0.50’ • Number of pallet positions high – 3 • Space above each pallet for racking system – 1.00’ • Honeycombing is 15% allowance with 20 cases on each pallet Question: Given the previous information give honeycombing at a 15 percent allowance with 20 cases on each pallet. Method (535 cu. ft.)/ [(1-15%) (60)] (535)/ [(0.85) (60)] 535/51.00 3 HONEYCOMBING Answer ...
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Anonymous
Really useful study material!

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