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Logarithm

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Mathematics
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log (2x+1) log 6 =2
Solution:
=log
10

= 2
=


=


= (2x+1) = 600
= 2x = 600-1
= 2x = 599
=


x = 299. 5
EXPLAINATION:
In solving logarithm there are rules to solve it. I use the
quotient rule because the equation uses the formula for
the difference of two logarithms and we use 10 as the
base because when there's no base written it is already
assumed as natural or base or 10 but since the final
answer is 2 we'll use 10. In the solution, when the
formula shows the difference of the two logarithm
equation, we will use the quotient rule as one of the basic
rules in logarithms and we will solve x by making the
base raised to the power of 2 as a result2x+16=102,
then we'll calculate 102 as 100 making it2x+16=100,
next we multiply 6 and 100 equals to 600 with a result of
2x+1=600, In the equation 2x+1, we'll move 1 to the
other side that's why it turned to negative 1and of course
for us to solve x as you see, Now it is 2x = 599 after that
we will divide it by 2 for both sides for us to know the
value of x which is the final answer is 299.5
Reference:
-https://www.intmath.com/exponential-logarithmic-
functions/3-logarithm-laws.php
-https://mathinsight.org/logarithm_basics#sitenav

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log (2x+1) – log 6 =2 EXPLAINATION: Solution: =log10 2𝑥+1 6 2x+1 = 6 2𝑥+1 =2 = 102 = 100 = (2x+1) = 600 = 2x = 600-1 = 2x = 599 2𝑥 599 = = = 6 2 2 x = 299. 5 In solving logarithm there are rules to solve it. I use the quotient rule because the equation uses the formula for ...
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