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Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Click this link to access the
Periodic Table.
This may be helpful throughout
the exam.
A reaction between HCl and NaOH is being studied in a styrofoam coffee cup
with a lid and the heat given off is measured by means of a thermometer
immersed in the reaction mixture. Enter the correct thermochemistry term
to describe the item listed.
1.
The type of thermochemical process
2.
The calorimeter and mixture of HCl
+
NaOH
Your Answer:
1.
The type of thermochemical process is an acid base reaction or
neutralization reaction where heat is given off called a exothermic reaction.
2.
The calorimeter and mixture of HCl
+
NaOH would be described as
enthalpy or the total energy of the system.
1.
Heat given off =
Exothermic
process
2.
With lid =
closed system
Question 1
Not yet graded / 10 pts
Question 2
Not yet graded / 10 pts
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Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Click this link to access the
Periodic Table.
This may be helpful throughout
the exam.
1.
Show the calculation of the final temperature of the mixture when a 31.6
g
r
am
s
a
mp
l
e
o
f
w
a
ter
a
t
92
.3
o
C
i
s
a
dded
to
a
40
.
5
g
r
am
s
a
mp
l
e
o
f
w
a
ter
a
t
25
.1
o
C
i
n
a
co
ff
ee
cup
c
a
l
o
r
i
me
ter
.
c
(
wa
ter)
=
4
.1
84
J
/
g
o
C
2.
Show the calculation of the energy involved in melting 85 grams of ice
a
t
0
o
C
i
f
the
H
e
a
t
o
f
F
us
i
on
f
o
r
wa
ter
i
s
0
.3
34
k
J
/
g
.
Your Answer:
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Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
1.
-
(
m
w
a
r
m
H
2
o
x
C
w
a
r
m
H
2
O
x
t
w
a
r
m
H
2
O
)
=
(
m
c
oo
l
H
2
O
x
c
c
oo
l
H
2
O
x
t
c
oo
l
H
2
O
)
-
[
31
.6
g
x
4
.
184
J
/
g
°C
x
(T
m
i
x
-
92
.3
°C)]
=
[
40
.
5
g
x
4
.1
84
J
/
g
°C
x
(T
m
i
x
-
25.1°C)]
-
[
132
.
2144
J
/
°C
x
(T
m
i
x
-
92
.3
°C)]
=
[
169
.4
52
J
/
°C
x
(T
m
i
x
-
25
.1
°C)]
-
132
.
2144
T
m
i
x
+
12
,
203
.3
891
=
169
.4
52
T
m
i
x
-
4
,
253
.
2452
16
,4
56
.6
343
=
301
.
6664
T
m
i
x
T
m
i
x
=
54
.5
5
°C
2.
q
I
s
=
m
x
H
f
u
s
i
on
q
I
s
=
85
g
x
0
.
334
k
J
/
g
q
I
s
=
28
.
39
k
J
a
nd
be
c
a
us
e
he
a
t
i
s
a
dded
+
28
.3
9
k
J
1.
-
(
m
w
a
r
n
H
2
O
x
c
w
a
r
n
H
2
O
x
t
w
a
r
n
H
2
O
)
=
(
m
c
oo
l
H
2
O
x
c
c
oo
l
H
2
O
x
t
c
oo
l
H
2
O
)
-
[
31
.6
g
x
4
.1
84
J
/
g
o
C
x
(T
m
i
x
-
92
.3
o
C
)]
=
[(
40
.5
g
x
4
.1
84
J
/
g
o
C
x
(T
m
i
x
-
25
.1
o
C
)]
-
[
132
.
2144
J
/
o
C
x
(T
m
i
x
-
92
.3
o
C
)]
=
[(
169
.4
52
J
/
o
C
x
(T
m
i
x
-
25
.1
o
C
)]
T
m
i
x
=
54
.
6
o
C
2.
q
l
s
=
m
x
H
f
u
s
i
on
=
85
g
x
0
.3
34
k
J
/
g
=
28
.
39
k
J
(
s
i
nce
he
a
t
i
s
a
dded
)
=
+
28.39 kJ
Click this link to access the
Periodic Table.
This may be helpful throughout
Question 3
Not yet graded / 10 pts
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Portage LearningCHEM 103module 3 exam with
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answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
the exam.
Show the calculation of the amount of heat involved if 18.3 g of S is reacted
wi
th
e
x
ce
ss
O
2
to
yi
e
l
d
s
ul
f
ur
tr
i
o
xi
de
b
y
the
f
o
ll
o
w
i
ng
r
e
a
cti
on
equation. Report your answer to 4 significant figures.
2
S
(
s
)
+
3
O
2
(
g
)
2
S
O
3
(
g
)
Δ
H
=
-
792
k
J
Your Answer:
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Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
2
S
(
s
)
+
3
O
2
(
g
)
2
S
O
3
(
g
)
Δ
H
=
-
792
k
J
H
r
x
=
2
mo
l
e
s
o
f
S
reaction uses 18.3 g S = 18.3/32.07 = 0.5706 mole S
q
=
H
r
x
x
ne
w
mo
l
e
s
/
o
r
i
g
i
na
l
mo
l
e
s
q
=
-792kJ x 0.5706 mole S
/
2 mole S
q
=
-225.9576 kJ
q = -226.0
2
S
(
s
)
+
3
O
2
(
g
)
2
S
O
3
(
g
)
Δ
H
=
-
792
k
J
Δ
H
r
x
i
s
f
o
r
2
mo
l
e
o
f
S
reaction uses 18.3 g S = 18.3/32.07 = 0.5706 mole S
q
=
Δ
H
r
x
x
ne
w
mo
l
e
s
/
o
r
i
g
i
na
l
mo
l
e
s
q
=
-792
kJ
x 0.5706 mole S
/
2 mole S
=
226.0
kJ
given off
Click this link to access the
Periodic Table.
This may be helpful throughout
the exam.
S
ho
w
th
e
ca
l
cul
a
ti
on
o
f
the
he
a
t
o
f
r
e
a
cti
on
(
Δ
H
r
x
n
)
f
o
r
the
r
e
a
cti
o
n:
2
Ca
(
s
)
+
2
C
(
g
r
a
p
hi
te)
+
3
O
2
(
g
)
2
CaCO
3
(
s
)
by using the following thermochemical data:
2
Ca
(
s
)
+
O
2
(
g
)
2
CaO
(
s
)
Δ
H
=
-
1270
.
18
k
J
C
(
g
r
a
p
hi
te)
+
O
2
(
g
)
CO
2
(
g
)
Δ
H
=
-
393
.5
1
k
J
Question 4
Not yet graded / 10 pts
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Portage LearningCHEM 103module 3 exam with
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Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
CaO
(
s
)
+
CO
2
(
g
)
CaCO
3
(
s
)
Δ
H
=
-
178
.3
2
k
J
Your Answer:
2
Ca
(
s
)
+
O
2
(
g
)
2
CaO
(
s
)
Δ
H
=
-
1270
.
18
k
J
C
(
g
r
a
p
hi
te)
+
O
2
(
g
)
CO
2
(
g
)
Δ
H
=
-
393
.
51
k
J
CaO
(
s
)
+
CO
2
(
g
)
CaCO
3
(
s
)
Δ
H
=
-
178
.
32
k
J
2
Ca
(
s
)
+
2
C
(
g
rap
h
i
t
e
)
+
3
O
2
(
g
)
2
CaCO
3
(
s
)
ΔH
r
x
n
ΔH
rxn
=
(1270.18)
+
2 x (-393.51)
+
2 x (-178.32)
ΔH
rxn
=
2413.84 kJ
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Portage LearningCHEM 103module 3 exam with
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answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
f
f f
f 2 6 f f
2
2
Ca
(
s
)
+
O
2
(
g
)
2
CaO
(s
)
Δ
H
=
-
1270.18 kJ
2
(
C
(
g
r
a
p
hi
te)
+
O
2
(
g
)
CO
2
(g
)
ΔH
=
- 393.51 kJ)
2
(
CaO
(s
)
+
CO
2
(g
)
CaCO
3
(
s
)
ΔH
=
- 178.32 kJ)
2 Ca (s)
+
2 C (graphite)
+
3
O
2
(
g
)
2
CaCO
3
(
s
)
Δ
H
rx
n
=
-
2413
.
84
k
J
Δ
H
rx
n
=
-
1270
.
18
+
2(-393
.
51
)
+
2(-178
.
32
)
=
-
2413
.
84
Click this link to access the
Periodic Table.
This may be helpful throughout
the exam.
S
ho
w
th
e
ca
l
cul
a
ti
on
o
f
the
he
a
t
o
f
r
e
a
cti
on
(
Δ
H
r
x
n
)
f
o
r
the
r
e
a
cti
o
n:
2
C
2
H
6
(
g
)
+
5
O
2
(
g
)
4
CO
(
g
)
+
6
H
2
O
(
l
)
by using the following thermochemical data:
ΔH
0
C H (g)
=
-84.0 kJ/mole, ΔH
0
CO (g)
=
-110.5 kJ/mole, ΔH
0
H O (l)
=
-285.8
kJ/mole
Your Answer:
2
C
2
H
6
(
g
)
+
5
O
2
(
g
)
4
CO
(
g
)
+
6
H
2
O
(
l
)
Δ
H
r
x
n
=
n
Δ
H
0
(
p
r
o
ducts
)
-
m
Δ
H
f
0
(r
e
a
ct
a
nts
)
Δ
H
r
x
n
=
4
Δ
H
f
0
(
CO
)
+
6
Δ
H
0
(
H
2
O
)
-
2
Δ
H
0
(
C
2
H
6
)
-
5
Δ
H
f
0
(
O
2
)
Δ
H
r
x
n
=
4
(
-
110
.5
k
J
/
mo
l
e
)
+
6
(
-285.8 kJ/mole
)
-
2
(
-
84
.
0
k
J
/
m
o
l
e
)
-
5
(
0
)
Δ
H
r
x
n
=
(
-
442
k
J
/
mo
l
)
+
(
-
1714
.8
k
J
/
mo
l
)
-
(
-
168
)
Δ
H
r
x
n
=
-
2
,1
56
.8
-
(
-
168
)
Question 5
Not yet graded / 10 pts
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Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Portage LearningCHEM 103module 3 exam with
answers LATEST UPDATE RATED A++
Δ
H
r
x
n
=
-
1
.9
88
.8
k
J
/
mo
l
2
C
2
H
6
(
g
)
+
5
O
2
(
g
)
4
CO
(
g
)
+
6
H
2
O
(
l
)
Δ
H
f
0
C
2
H
6
(
g
)
=
-
84
.0
k
J
/
mo
l
e
,
Δ
H
f
0
CO
(
g
)
=
-
110
.
5
k
J
/
m
o
l
e
,
Δ
H
f
0
H
2
O
(
l
)
=
-
285
.8
kJ/mole
Δ
H
rx
n
=
2
(+
84
.
0
)
+
5
(0
)
+
4(-110
.
5
)
+
6(-285
.
8
)
=
-
1988
.
8
k
J
/
mo
le
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