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The questions in this section are to be answered by circling the correct multiple-choice answer AND providing a short justification of your answer in the space after the problem..
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Explanation & Answer
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Running head: Homework on electrical potential
Name of student
Name of professor
Name of course
Name of institution
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Homework on electrical potential
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Question 5.1
If a positive or a negative charge are introduced inside a conductor, a surface charge is set up in a
conductor which then creates an electric field which exerts force on the conductor charges and pushes
them away from one another to the conductor surface and when they reach a conductor surface, they
spread away such that charges and electric field inside a conductor vanish (Fernandez, 1977).
Answer = (d) A surface charge is set up that creates an electric field which cancels the applied
field.
Question 5.2
surface charge density on the left side of the slab = ∇ ⋅ P.
P = χ ε0 E
Where χ = scalar quantity = 1
ε0 =Electric constant =8.854187817*10^-12C2/NM2
E = electric field
P = polarization density
Hence polarization density outside the slab = χ ε0 E where E= outside electric field
1*8.854187817*10^-12 *10 = 8.854187817*10^11C/m2
And polarization density inside the slab = χ ε0 E where E= inside electric field
1*8.854187817*10^-12* 3.5 = 3.0989*10^-11 C/m2
Surface charge density on the left side = Inside polarization charge density – outside charge
density
3.0989*10^-11 -8.854187817*10^-11 = -5.7551 = -5.8 C/m2
Answer = (d) −5.8 × 10^−11C/m2
Homework on electrical potential
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Question 5.3
Total charge = total surface charge of a cavity + total charge of a point in a cavity +total charge
of outer surface of dielectric
Total charge of a point in a cavity =+Q.
Total charge of a surface of the cavity = +2Q.
Total charge of outer surface of a dielectric = −Q.
Total charge = =(+Q) +(+2Q) +(-Q) = +2Q
Answer = (c) +2Q.
Question 5.4
Induce charge = σ (1+ (±1/𝐾)
Wh...