# How to solve algebra questions

*label*Algebra

*timer*Asked: Mar 21st, 2014

**Question description**

I need help with an algebra equation. Here is the set up.

A father is looking for the best option for daycare for his 5 year old son. A
home-based option (Option A) charges a flat rate per hour of $15. A
center-based option (option B) charges a fixed fee per week of $150 for 40
hours and $10 an hour for any hour over the 40. What is the best option for the
father? The father works 50 hours a week from his office which is located in his
home.

x = number of hours

y = total child care cost

Option A: (A)y = 15x

Option B1: (B1)y= 150 10 (x-40)**My paper got sent back because it said I
need an additional equation for Option B that represents less than 40 hours of
daycare is needed to complete the assessment.**

This is what I came up with.

Option B2: (B2)y=150 10x, x≥40 hours – day care with less than 40

Is this right?????? But I am not sure how to solve this. **If that is right I need to show when option
A and option B2 will be equal. How do I do that? I also need to be able to
graph it so I will need an ordered pair.**

I already submitted my paper fixing option A instead of B showing that equation with less than 50 hours a week (less than 40 y=15[img width="9" height="25" src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAkAAAAZCAMAAADUmfS5AAAAAXNSR0IArs4c6QAAADZQTFRFAAAAAAAAAAA6ADqQOgAAOjqQOpDbZjqQZrb/kDoAkNv/tmYA25A629uQ2//b2////9uQ// 2iqJ94wAAAAF0Uk5TAEDm2GYAAAAJcEhZcwAAEnQAABJ0Ad5mH3gAAAAZdEVYdFNvZnR3YXJlAE1pY3Jvc29mdCBPZmZpY2V/7TVxAAAAM0lEQVQYV2NgoCUQYOUHG8/NJsjOx8kBYvIwMjJxgQWBLGawNEiWlwUsywDTQUtXQcwGAIliAQ0yGICAAAAAAElFTkSuQmCC" v:shapes="_x0000_i1025"