Determinant for vector cross product

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Mathematics

Description

Find the determinant of the following i j k 5 0 3 7 1 9

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Explanation & Answer

Set up a determinant: 

| i  j  k |
| 5 0  3 |
| 7 7  9 |

  Now calculate the determinant, using the first row as your cofactors:
  (0 - 21)i - (45 - 21)j + (35 - 0)k  =  -21i - 24j + 35k 

  The cross product is the vector -21i + 24j + 35k



Anonymous
Very useful material for studying!

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