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10, A = (-2.1), B = (3, -3), C = (7,5), D (3,6), E (8,2), F (10.11), Using Distance Formula, we get the following lengths:
AB = (-3-1)^2 + (3- (-2)^2; 16 + 25 = 41, SQRT 41 = 6.5
BC = (5 - (-3))^2 + (7 - 3)^2; 64 + 16 = 80 SQRT 80 = 8.9
AC = (5-1)^2 + (7 - (-2))^2; 16 + 81 = 97 SQRT 97 = 9.8
DE (2- (-6)^2 + (8-3)^2; 64 + 25 = 89 SQRT 89 = 9.4
EF (11-2)^2 + (10-8)^2; 81 + 4 = 85 SQRT 85 = 9.2
DF (11-6)^2 + (10 - 3)^2; 25 + 49 = 74 SQRT 74 = 8.6
No, the triangles are not similar.
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