# Algebra??????? help please

**Question description**

Find an equation of the circle that satisfies the given conditions.

Center (3, −3);radius 4

Center (−1, −9);radius 5Center at the origin;passes through (4, 9)

Center (−2, 1);passes through (9, 6)

Endpoints of a diameter are P(−2, 1) and Q(8, 9).

Endpoints of a diameter are P(−2, 1) and Q(4, −5).

Show that the equation represents a circle by rewriting it in standard form, and find the center and radius of the circle.

^{2}+ y

^{2}− 6x + 8y + 21 = 0

^{2}+ y

^{2}− 2x − 2y = 14

^{2}+ y

^{2}− 8x + 8y + 16 = 0

^{2}+ y

^{2}+ 10y + 18 = 0

^{2}+ y

^{2}+ x = 0

^{2}+ y

^{2}+ 6x + y + 9 = 0

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