Description
A chemist takes 6.0 L of 3.5 KOH and dilutes its to make 12.5 L. What is the new concentration of the diluted KOH?
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Explanation & Answer
let C1 represent the initial concentration and V1 the initial volume let let C2 represent the final concentration and V2 the final volume
CIVI=C2V2
6*3.5=12.5*V2
WHEN YOU DIVIDE BOTH SIDES BY12.5,
V2=1.68M
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