Description
given 2CO(g) + O2(g) 2CO2(g) K = 3.01×1091
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Explanation & Answer
Follow these steps : 2CO (g) + O2 (g) ---->. 2CO2 (g). call it eq. 1
C (graphite) + 1/2 O2 (g) -----> CO (g) call it eq.2
C (graphite) + O2 -------> CO2 (g). call it eq 3
Now multiply sq. 2 by2 band add to sq. 1
You get 2 C (graphite) + 2 O2 (g) -----> 2CO2
Divide by 2 and you get C (graphite) + O2 -------> CO2
k1 = [CO2]^2/ [CO]^2 [O2]. And k2 = [CO]/ [C graph][O2]^1/2
And 2k2 = [CO]^2/ [Cgr]^2 [O2}
So k overall =. sqrt ( k1 x 2k2)
= sqrt ( 3.01 x 10^91 multiplied by 2 x 2.28 10^23
k overall =. sqrt ( 13.7 x 10^ 114)
= 3.7 x 10^ 57
Answer: equilibrium constant for eq. 3 = 3.7 x 10 ^ 57
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